Difference between revisions of "2008 AIME I Problems/Problem 7"
(→See also) |
|||
| Line 11: | Line 11: | ||
== See also == | == See also == | ||
{{AIME box|year=2008|n=I|num-b=6|num-a=8}} | {{AIME box|year=2008|n=I|num-b=6|num-a=8}} | ||
| + | |||
| + | Video Solution: | ||
| + | https://www.youtube.com/watch?v=6eBLXnzK0n4 | ||
| + | |||
[[Category:Intermediate Number Theory Problems]] | [[Category:Intermediate Number Theory Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 04:11, 4 May 2020
Problem
Let
be the set of all integers
such that
. For example,
is the set
. How many of the sets
do not contain a perfect square?
Solution
The difference between consecutive squares is
, which means that all squares above
are more than
apart.
Then the first
sets (
) each have at least one perfect square. Also, since
(which is when
), there are
other sets after
that have a perfect square.
There are
sets without a perfect square.
See also
| 2008 AIME I (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
Video Solution:
https://www.youtube.com/watch?v=6eBLXnzK0n4
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.