Difference between revisions of "2011 AMC 8 Problems/Problem 22"
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<math> \textbf{(A) }0\qquad\textbf{(B) }1\qquad\textbf{(C) }3\qquad\textbf{(D) }4\qquad\textbf{(E) }7 </math> | <math> \textbf{(A) }0\qquad\textbf{(B) }1\qquad\textbf{(C) }3\qquad\textbf{(D) }4\qquad\textbf{(E) }7 </math> | ||
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| + | ==Video Solution== | ||
| + | https://youtu.be/7an5wU9Q5hk?t=1710 | ||
==Solution 1== | ==Solution 1== | ||
Revision as of 19:15, 27 October 2020
Contents
Problem
What is the tens digit of 
?
Video Solution
https://youtu.be/7an5wU9Q5hk?t=1710
Solution 1
We want the tens digit
So, we take 
. That is congruent to 
. From here, it is an easy bash, 7, 49, 43, 01, 07, 49, 43, 01, 07, 49, 43. So the answer is 
See Also
| 2011 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 21 |
Followed by Problem 23 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
