Difference between revisions of "2011 AMC 8 Problems/Problem 14"
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<math> \textbf{(A) } \dfrac7{18} \qquad\textbf{(B) } \dfrac7{15} \qquad\textbf{(C) } \dfrac{22}{45} \qquad\textbf{(D) } \dfrac12 \qquad\textbf{(E) } \dfrac{23}{45} </math> | <math> \textbf{(A) } \dfrac7{18} \qquad\textbf{(B) } \dfrac7{15} \qquad\textbf{(C) } \dfrac{22}{45} \qquad\textbf{(D) } \dfrac12 \qquad\textbf{(E) } \dfrac{23}{45} </math> | ||
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| + | ==Video Solution== | ||
| + | https://youtu.be/rQUwNC0gqdg?t=697 | ||
==Solution== | ==Solution== | ||
Revision as of 19:33, 27 October 2020
Contents
Problem
There are 
students at Colfax Middle School, where the ratio of boys to girls is 
. There are 
students at Winthrop Middle School, where the ratio of boys to girls is 
. The two schools hold a dance and all students from both schools attend. What fraction of the students at the dance are girls?
Video Solution
https://youtu.be/rQUwNC0gqdg?t=697
Solution
At Colfax Middle School, there are 
girls. At Winthrop Middle School, there are 
girls. The ratio of girls to the total number of students is 
See Also
| 2011 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
