Difference between revisions of "2020 AMC 12A Problems/Problem 1"
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| − | If Carlos took <math>70\%</math> of the pie, there must be <math>(100 - 70) = 30\%</math>. After Maria takes <math>\frac{1}{3}</math> of the remaining <math>30\%, </math> | + | If Carlos took <math>70\%</math> of the pie, there must be <math>(100 - 70) = 30\%</math> left. After Maria takes <math>\frac{1}{3}</math> of the remaining <math>30\%, </math> |
<math>1 - \frac{1}{3} = \frac{2}{3}</math> is left. | <math>1 - \frac{1}{3} = \frac{2}{3}</math> is left. | ||
Revision as of 23:38, 28 November 2020
Contents
Problem
Carlos took 
of a whole pie. Maria took one third of the remainder. What portion of the whole pie was left?
Solution 1
If Carlos took of the pie, there must be 
left. After Maria takes 
of the remaining 
is left.
Therefore:
-Contributed by YOur dad, one dude
Video Solution
~IceMatrix
See Also
| 2020 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
