Difference between revisions of "2021 AMC 12A Problems/Problem 25"
Lopkiloinm (talk | contribs) (→Solution) |
Sugar rush (talk | contribs) |
||
| Line 8: | Line 8: | ||
~Lopkiloinm | ~Lopkiloinm | ||
| − | |||
| − | |||
==See also== | ==See also== | ||
{{AMC12 box|year=2021|ab=A|num-b=24|after=Last problem}} | {{AMC12 box|year=2021|ab=A|num-b=24|after=Last problem}} | ||
| + | |||
| + | [[Category:Intermediate Number Theory Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 15:10, 11 February 2021
Problem
Let
denote the number of positive integers that divide
, including
and
. For example,
and
. (This function is known as the divisor function.) Let
There is a unique positive integer
such that
for all positive integers
. What is the sum of the digits of
Solution
Start off with the number x that does not have a factor of 3. Multiply x by 9. Multiplying x by 9 triples the number of divisors and divison by
. The number is now
. Multiplying a nonmultiple of 3 by 9 making a bigger f leads to this truth being known,
. A property of multiples of 9 is their digits add up to 9, so the only possibility is
~Lopkiloinm
See also
| 2021 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 24 |
Followed by Last problem |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.