Difference between revisions of "1993 AJHSME Problems/Problem 12"
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==Problem== | ==Problem== | ||
| − | If each of the three operation signs, <math>+</math>, <math>-</math>, <math>\times </math>, is used exactly ONCE in one of the blanks in the expression | + | If each of the three operation signs, <math>+</math>, <math>\text{--}</math>, <math>\times </math>, is used exactly ONCE in one of the blanks in the expression |
<cmath>5\hspace{1 mm}\underline{\hspace{4 mm}}\hspace{1 mm}4\hspace{1 mm}\underline{\hspace{4 mm}}\hspace{1 mm}6\hspace{1 mm}\underline{\hspace{4 mm}}\hspace{1 mm}3</cmath> | <cmath>5\hspace{1 mm}\underline{\hspace{4 mm}}\hspace{1 mm}4\hspace{1 mm}\underline{\hspace{4 mm}}\hspace{1 mm}6\hspace{1 mm}\underline{\hspace{4 mm}}\hspace{1 mm}3</cmath> | ||
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==Solution== | ==Solution== | ||
| + | There are a reasonable number of ways to place the operation signs, so guess and check to find that <math>5-4+6 \times 3 = \boxed{\text{(E)}\ 19}</math>. | ||
| + | |||
| + | ==See Also== | ||
| + | {{AJHSME box|year=1993|num-b=11|num-a=13}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 23:47, 15 January 2023
Problem
If each of the three operation signs,
,
,
, is used exactly ONCE in one of the blanks in the expression
then the value of the result could equal
Solution
There are a reasonable number of ways to place the operation signs, so guess and check to find that
.
See Also
| 1993 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 11 |
Followed by Problem 13 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.