Difference between revisions of "2023 AMC 8 Problems/Problem 24"
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| + | ==Problem== | ||
| + | Isosceles <math>\triangle ABC</math> has equal side lengths <math>AB</math> and <math>BC</math>. In the figure below, segments are drawn parallel to <math>\overline{AC}</math> so that the shaded portions of <math>\triangle ABC</math> have the same area. The heights of the two unshaded portions are 11 and 5 units, respectively. What is the height of <math>h</math> of <math>\triangle ABC</math>? | ||
| + | *Add asymptote diagram* | ||
| + | |||
| + | <cmath>\textbf{(A) } 14.6 \qquad \textbf{(B) } 14.8 \qquad \textbf{(C) } 15 \qquad \textbf{(D) } 15.2 \qquad \textbf{(E) } ~15.4</cmath> | ||
| + | \end{exx} | ||
| + | |||
| + | ==Video Solution== | ||
| + | |||
| + | https://youtu.be/almtw4n-92A | ||
Revision as of 18:22, 24 January 2023
Problem
Isosceles
has equal side lengths
and
. In the figure below, segments are drawn parallel to
so that the shaded portions of
have the same area. The heights of the two unshaded portions are 11 and 5 units, respectively. What is the height of
of
?
- Add asymptote diagram*
\end{exx}