Difference between revisions of "2012 AMC 12B Problems/Problem 3"
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For a science project, Sammy observed a chipmunk and squirrel stashing acorns in holes. The chipmunk hid 3 acorns in each of the holes it dug. The squirrel hid 4 acorns in each of the holes it dug. They each hid the same number of acorns, although the squirrel needed 4 fewer holes. How many acorns did the chipmunk hide? | For a science project, Sammy observed a chipmunk and squirrel stashing acorns in holes. The chipmunk hid 3 acorns in each of the holes it dug. The squirrel hid 4 acorns in each of the holes it dug. They each hid the same number of acorns, although the squirrel needed 4 fewer holes. How many acorns did the chipmunk hide? | ||
| + | <math>\textbf{(A)}\ 30\qquad\textbf{(B)}\ 36\qquad\textbf{(C)}\ 42\qquad\textbf{(D)}\ 48\qquad\textbf{(E)}\ 54</math> | ||
==Solution== | ==Solution== | ||
| − | If x is the number of holes that the chipmunk dug then | + | If <math>x</math> is the number of holes that the chipmunk dug, then <math>3x=4(x-4)</math>, so <math>3x=4x-16</math>, and <math>x=16</math>. The number of acorns hidden by the chipmunk is equal to <math>3x = \boxed{\textbf{(D)}\ 48}</math> |
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| + | ==Solution 2== | ||
| + | Trying answer choices, we see that <math>\boxed{\textbf{(D)}\ 48}</math> works. ~Extremelysupercooldude | ||
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| + | == See Also == | ||
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| + | {{AMC12 box|year=2012|ab=B|num-b=2|num-a=4}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 06:12, 29 June 2023
Contents
Problem
For a science project, Sammy observed a chipmunk and squirrel stashing acorns in holes. The chipmunk hid 3 acorns in each of the holes it dug. The squirrel hid 4 acorns in each of the holes it dug. They each hid the same number of acorns, although the squirrel needed 4 fewer holes. How many acorns did the chipmunk hide?
Solution
If 
is the number of holes that the chipmunk dug, then 
, so 
, and 
. The number of acorns hidden by the chipmunk is equal to 
Solution 2
Trying answer choices, we see that 
works. ~Extremelysupercooldude
See Also
| 2012 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 2 |
Followed by Problem 4 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
