Difference between revisions of "2023 AMC 10B Problems/Problem 10"

Latest revision as of 19:30, 15 November 2023

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+#redirect[[2023 AMC 12B Problems/Problem 5]]
-== Solution 1 ==
-First, note that since the rectangle covers 2 squares, we only need to guess squares that are not adjacent to any of our other guesses. There are only two ways to do this: one with <math>5</math> guesses, and one with <math>4</math>. Since the problem is asking for the minimum number, the answer is <math>\boxed{\text{(C) }   4}</math>.
-~yourmomisalosinggame (a.k.a. Aaron)