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Difference between revisions of "2013 IMO Problems/Problem 5"
 
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Prove that <math>f(x)=x</math> for all <math>x\in\mathbb Q_{>0}</math>.
 
Prove that <math>f(x)=x</math> for all <math>x\in\mathbb Q_{>0}</math>.
  
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Proposed by Bulgaria
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==Solution==
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{{solution}}
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==See Also==
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*[[2013 IMO]]
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{{IMO box|year=2013|num-b=4|num-a=6}}

Latest revision as of 00:32, 19 November 2023

Problem

Let $\mathbb Q_{>0}$ be the set of all positive rational numbers. Let $f:\mathbb Q_{>0}\to\mathbb R$ be a function satisfying the following three conditions:

(i) for all $x,y\in\mathbb Q_{>0}$, we have $f(x)f(y)\geq f(xy)$; (ii) for all $x,y\in\mathbb Q_{>0}$, we have $f(x+y)\geq f(x)+f(y)$; (iii) there exists a rational number $a>1$ such that $f(a)=a$.

Prove that $f(x)=x$ for all $x\in\mathbb Q_{>0}$.

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See Also

2013 IMO (Problems) • Resources
Preceded by
Problem 4 		1 • 2 • 3 • 4 • 5 • 6 Followed by
Problem 6
All IMO Problems and Solutions
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