Difference between revisions of "1970 AMC 12 Problems/Problem 2"
(New page: A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is) |
|||
| Line 1: | Line 1: | ||
| + | == Problem == | ||
| + | |||
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | ||
| + | |||
| + | <math> \mathrm{(A) \ } -h\qquad \mathrm{(B) \ } 0\qquad \mathrm{(C) \ } h\qquad \mathrm{(D) \ } 2h</math> | ||
| + | |||
| + | <math>\mathrm{(E) \ } h^3</math> | ||
| + | |||
| + | == Solution == | ||
Revision as of 11:29, 9 January 2008
Problem
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is
