Difference between revisions of "2002 AMC 10P Problems/Problem 2"
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| − | + | == Problem 2 == | |
| + | The sum of eleven consecutive integers is <math>2002.</math> What is the smallest of these integers? | ||
| + | |||
| + | <math> | ||
| + | \text{(A) }175 | ||
| + | \qquad | ||
| + | \text{(B) }177 | ||
| + | \qquad | ||
| + | \text{(C) }179 | ||
| + | \qquad | ||
| + | \text{(D) }180 | ||
| + | \qquad | ||
| + | \text{(E) }181 | ||
| + | </math> | ||
| + | |||
| + | == Solution 1 == | ||
| + | |||
| + | == See Also == | ||
Revision as of 06:48, 15 July 2024
Problem 2
The sum of eleven consecutive integers is 
What is the smallest of these integers?
