Difference between revisions of "2011 CEMC Gauss (Grade 8) Problems/Problem 3"

(Created page with "==Problem== In the diagram, the value of <math>y</math> is: <math> \text{ (A) }\ 60 \qquad\text{ (B) }\ 100\qquad\text{ (C) }\ 120\qquad\text{ (D) }\ 180\qquad\text{ (E) }\ 2...")
 
 
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==Problem==
 
==Problem==
In the diagram, the value of <math>y</math> is:
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In the diagram, the value of <math>y</math> is
 
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{{Template:Image needed}}
 
<math> \text{ (A) }\ 60 \qquad\text{ (B) }\ 100\qquad\text{ (C) }\ 120\qquad\text{ (D) }\ 180\qquad\text{ (E) }\ 270 </math>
 
<math> \text{ (A) }\ 60 \qquad\text{ (B) }\ 100\qquad\text{ (C) }\ 120\qquad\text{ (D) }\ 180\qquad\text{ (E) }\ 270 </math>
 
==Solution==
 
==Solution==
One entire revolution is <math>360^{\circ}</math>. As suggested by the diagram, the given part of the angle is <math>90^{\circ}</math>. This means that we have:
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One entire revolution is <math>360^{\circ}</math>. As suggested by the diagram, the given part of the angle is a [[right angle]]. This means that we have:
  
 
<math>y^{\circ} + 90^{\circ} = 360^{\circ}</math>
 
<math>y^{\circ} + 90^{\circ} = 360^{\circ}</math>

Latest revision as of 12:18, 22 April 2025

Problem

In the diagram, the value of $y$ is


An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.


$\text{ (A) }\ 60 \qquad\text{ (B) }\ 100\qquad\text{ (C) }\ 120\qquad\text{ (D) }\ 180\qquad\text{ (E) }\ 270$

Solution

One entire revolution is $360^{\circ}$. As suggested by the diagram, the given part of the angle is a right angle. This means that we have:

$y^{\circ} + 90^{\circ} = 360^{\circ}$

Solving for y gives:

$y = \boxed {\textbf {(E) } 270}$

~anabel.disher