Difference between revisions of "2022 AMC 8 Problems/Problem 4"
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size(3cm); | size(3cm); | ||
draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,0.25)); | draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,0.25)); | ||
| − | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); | + | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); |
</asy> | </asy> | ||
When <b>M</b> is then reflected over the line <math>p,</math> we obtain the following diagram: | When <b>M</b> is then reflected over the line <math>p,</math> we obtain the following diagram: | ||
| Line 48: | Line 48: | ||
size(3cm); | size(3cm); | ||
draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,-0.25)); | draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,-0.25)); | ||
| − | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); | + | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); |
</asy> | </asy> | ||
Therefore, the answer is <math>\boxed{\textbf{(E)}}.</math> | Therefore, the answer is <math>\boxed{\textbf{(E)}}.</math> | ||
~MRENTHUSIASM | ~MRENTHUSIASM | ||
| + | |||
| + | ==Video Solution (A Clever Explanation You’ll Get Instantly)== | ||
| + | https://youtu.be/tYWp6fcUAik?si=V8hv_zOn_zYOi9E5&t=350 | ||
| + | ~hsnacademy | ||
| + | |||
| + | ==Video Solution 1 by Math-X (First understand the problem!!!)== | ||
| + | https://youtu.be/oUEa7AjMF2A?si=l-XMI73aofM6q4ye&t=320 | ||
| + | |||
| + | ~Math-X | ||
| + | |||
| + | ==Video Solution 2 (CREATIVE THINKING!!!)== | ||
| + | https://youtu.be/lItyKxX_qB8 | ||
| + | |||
| + | ~Education, the Study of Everything | ||
| + | |||
| + | ==Video Solution 3== | ||
| + | https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=259 | ||
| + | |||
| + | ~Interstigation | ||
| + | |||
| + | ==Video Solution 4== | ||
| + | https://youtu.be/c-D-bj2htGE | ||
| + | |||
| + | ~savannahsolver | ||
| + | |||
| + | ==Video Solution 5== | ||
| + | https://youtu.be/Q0R6dnIO95Y?t=182 | ||
| + | |||
| + | ~STEMbreezy | ||
| + | |||
| + | ==Video Solution 6== | ||
| + | https://www.youtube.com/watch?v=6kkJVsOKcuk | ||
| + | |||
| + | ~harungurcan | ||
| + | |||
| + | ==Video Solution 7 by Dr. David== | ||
| + | |||
| + | https://youtu.be/hh3DbQ9Rd5Y | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2022|num-b=3|num-a=5}} | {{AMC8 box|year=2022|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
| + | |||
| + | [[Category:Introductory Geometry Problems]] | ||
Latest revision as of 16:48, 4 June 2025
Contents
- 1 Problem
- 2 Solution
- 3 Video Solution (A Clever Explanation You’ll Get Instantly)
- 4 Video Solution 1 by Math-X (First understand the problem!!!)
- 5 Video Solution 2 (CREATIVE THINKING!!!)
- 6 Video Solution 3
- 7 Video Solution 4
- 8 Video Solution 5
- 9 Video Solution 6
- 10 Video Solution 7 by Dr. David
- 11 See Also
Problem
The letter M in the figure below is first reflected over the line
and then reflected over the line
. What is the resulting image?
Solution
When M is first reflected over the line
we obtain the following diagram:
When M is then reflected over the line
we obtain the following diagram:
Therefore, the answer is
~MRENTHUSIASM
Video Solution (A Clever Explanation You’ll Get Instantly)
https://youtu.be/tYWp6fcUAik?si=V8hv_zOn_zYOi9E5&t=350 ~hsnacademy
Video Solution 1 by Math-X (First understand the problem!!!)
https://youtu.be/oUEa7AjMF2A?si=l-XMI73aofM6q4ye&t=320
~Math-X
Video Solution 2 (CREATIVE THINKING!!!)
~Education, the Study of Everything
Video Solution 3
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=259
~Interstigation
Video Solution 4
~savannahsolver
Video Solution 5
https://youtu.be/Q0R6dnIO95Y?t=182
~STEMbreezy
Video Solution 6
https://www.youtube.com/watch?v=6kkJVsOKcuk
~harungurcan
Video Solution 7 by Dr. David
See Also
| 2022 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.