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Difference between revisions of "1998 CEMC Pascal Problems/Problem 2"

(Created page with "==Problem== If <math>3(x - 5) = 3(18 - 5)</math>, then <math>x</math> is <math> \text{ (A) }\ \frac{44}{3} \qquad\text{ (B) }\ \frac{32}{3} \qquad\text{ (C) }\ 9 \qquad\text{...")
 
 
Line 26: Line 26:
 
~anabel.disher
 
~anabel.disher
 
==Solution 2==
 
==Solution 2==
−
We can notice that the left side of the equation is just like the right side of the equation. This allows us to see <math>x = 18</math>.
+
We can notice that the left side of the equation is just like the right side of the equation. This allows us to see <math>x = \boxed {\textbf {(D) } 18}</math>.
  
 
~anabel.disher
 
~anabel.disher

Latest revision as of 16:47, 22 June 2025

Problem

If $3(x - 5) = 3(18 - 5)$, then $x$ is

$\text{ (A) }\ \frac{44}{3} \qquad\text{ (B) }\ \frac{32}{3} \qquad\text{ (C) }\ 9 \qquad\text{ (D) }\ 18 \qquad\text{ (E) }\ 81$

Solution 1

$3(x - 5) = 3(18 - 5)$

$3x - 15 = 3 \times 13$

$3x - 15 = 39$

$3x = 54$

$x = \boxed {\textbf {(D) } 18}$

~anabel.disher

Solution 1.5

$3(x - 5) = 3(18 - 5)$

$3(x - 5) = 3 \times 13$

$x - 5 = 13$

$x = \boxed {\textbf {(D) } 18}$

~anabel.disher

Solution 2

We can notice that the left side of the equation is just like the right side of the equation. This allows us to see $x = \boxed {\textbf {(D) } 18}$.

~anabel.disher

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