Difference between revisions of "1972 AHSME Problems/Problem 11"

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==Problem==
 
==Problem==
The value(s) of <math>y</math> for which the following pair of equations <math>x^2+y^2+16=0\text{ and }x^2-3y+12=0</math> may have a real common solution, are
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The value(s) of <math>y</math> for which the following pair of equations <math>x^2+y^2-16=0\text{ and }x^2-3y+12=0</math> may have a real common solution, are
  
 
<math>\textbf{(A) }4\text{ only}\qquad \textbf{(B) }-7,~4\qquad \textbf{(C) }0,~4\qquad \textbf{(D) }\text{no }y\qquad  \textbf{(E) }\text{all }y</math>
 
<math>\textbf{(A) }4\text{ only}\qquad \textbf{(B) }-7,~4\qquad \textbf{(C) }0,~4\qquad \textbf{(D) }\text{no }y\qquad  \textbf{(E) }\text{all }y</math>
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==Solution==
 
==Solution==
  

Revision as of 14:24, 28 June 2025

Problem

The value(s) of $y$ for which the following pair of equations $x^2+y^2-16=0\text{ and }x^2-3y+12=0$ may have a real common solution, are

$\textbf{(A) }4\text{ only}\qquad \textbf{(B) }-7,~4\qquad \textbf{(C) }0,~4\qquad \textbf{(D) }\text{no }y\qquad  \textbf{(E) }\text{all }y$

Solution

Because x2 + y2 + 16 = 0 has no real solutions, ∀ sets containing x2 + y2 + 16 = 0, no real solutions may exist.

∴ the solution is $\fbox{D}$


– TylerO_1.618