Difference between revisions of "1972 AHSME Problems/Problem 11"
Tylero 1.618 (talk | contribs) (→Solution) |
(→Solution) |
||
(2 intermediate revisions by 2 users not shown) | |||
Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
− | The value(s) of <math>y</math> for which the following pair of equations <math>x^2+y^2 | + | The value(s) of <math>y</math> for which the following pair of equations <math>x^2+y^2-16=0\text{ and }x^2-3y+12=0</math> may have a real common solution, are |
<math>\textbf{(A) }4\text{ only}\qquad \textbf{(B) }-7,~4\qquad \textbf{(C) }0,~4\qquad \textbf{(D) }\text{no }y\qquad \textbf{(E) }\text{all }y</math> | <math>\textbf{(A) }4\text{ only}\qquad \textbf{(B) }-7,~4\qquad \textbf{(C) }0,~4\qquad \textbf{(D) }\text{no }y\qquad \textbf{(E) }\text{all }y</math> | ||
− | |||
− | + | ==Solution (Rigorous) == | |
− | |||
− | + | ==Solution (Quick)== | |
+ | Checking the answer choices, we see that only 4 is the viable choice. Therefore, the answer is <math>\boxed{A}</math> |
Latest revision as of 14:27, 28 June 2025
Problem
The value(s) of for which the following pair of equations
may have a real common solution, are
Solution (Rigorous)
Solution (Quick)
Checking the answer choices, we see that only 4 is the viable choice. Therefore, the answer is