Difference between revisions of "2025 AMC 8 Problems/Problem 7"

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On the most recent exam on Prof. Xochi's class,  
 
On the most recent exam on Prof. Xochi's class,  
  
 +
* <math>5</math> students earned a score of at least <math>95\%</math>,
  
<math>5</math> students earned a score of at least <math>95\%</math>,  
+
* <math>13</math> students earned a score of at least <math>90\%</math>,  
  
<math>13</math> students earned a score of at least <math>90\%</math>,
+
* <math>27</math> students earned a score of at least <math>85\%</math>,  
 
 
<math>27</math> students earned a score of at least <math>85\%</math>,
 
 
 
<math>50</math> students earned a score of at least <math>80\%</math>,  
 
  
 +
* <math>50</math> students earned a score of at least <math>80\%</math>,
  
 
How many students earned a score of at least <math>80\%</math> and less than <math>90\%</math>?
 
How many students earned a score of at least <math>80\%</math> and less than <math>90\%</math>?

Latest revision as of 20:09, 25 September 2025

Problem

On the most recent exam on Prof. Xochi's class,

  • $5$ students earned a score of at least $95\%$,
  • $13$ students earned a score of at least $90\%$,
  • $27$ students earned a score of at least $85\%$,
  • $50$ students earned a score of at least $80\%$,

How many students earned a score of at least $80\%$ and less than $90\%$?

$\textbf{(A)}\ 8\qquad \textbf{(B)}\ 14\qquad \textbf{(C)}\ 22\qquad \textbf{(D)}\ 37\qquad \textbf{(E)}\ 45$

Solution 1

$50$ people scored at least $80\%$, and out of these $50$ people, $13$ of them earned a score that was not less than $90\%$, so the number of people that scored in between at least $80\%$ and less than $90\%$ is $50-13 = \boxed{\text{(D)\ 37}}$.

~Soupboy0

Solution 2

Let $a$ denote the number of people who had a score of at least $85$, but less than $90$, and let $b$ denote the number of people who had a score of at least $80$ but less than $85$. Our answer is equal to $a+b$. We find $a = 27 - 13 = 14$, while $b = 50 - 27 = 23$. Thus, the answer is $23 + 14 = \boxed{\text{(D)\ 37}}$.

-vockey

Video Solution 1 by Cool Math Problems

https://youtu.be/BRnILzqVwHk?si=kOvMjPSxqVZR8Mmt&t=89

Video Solution 2 by SpreadTheMathLove

https://www.youtube.com/watch?v=jTTcscvcQmI

Video Solution 3

~hsnacademy

Video Solution 4 by Thinking Feet

https://youtu.be/PKMpTS6b988

Video Solution 5 by Daily Dose of Math

~Thesmartgreekmathdude

Video Solution(Quick, fast, easy!)

https://youtu.be/fdG7EDW_7xk

~MC

See Also

2025 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. AMC Logo.png