Difference between revisions of "Euc20191/Sub-Problem 2"

(Created page with "==Problem== What integer <math>a</math> satisfies <math>3<\frac{24}{a}<4</math>?")
 
 
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What integer <math>a</math> satisfies <math>3<\frac{24}{a}<4</math>?
 
What integer <math>a</math> satisfies <math>3<\frac{24}{a}<4</math>?
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==Solution==
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If <math>a=6</math>, then <math>\frac{24}{6}=4</math> and if <math>a=8</math>, then <math>\frac{24}{8}=3</math>. So, <math>a</math> has to be between <math>6</math> and <math>8</math>, and therefore, it has to be <math>\boxed{7}</math>.
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~Yuhao2012

Latest revision as of 11:32, 13 October 2025

Problem

What integer $a$ satisfies $3<\frac{24}{a}<4$?

Solution

If $a=6$, then $\frac{24}{6}=4$ and if $a=8$, then $\frac{24}{8}=3$. So, $a$ has to be between $6$ and $8$, and therefore, it has to be $\boxed{7}$.

~Yuhao2012