Difference between revisions of "2012 CEMC Gauss (Grade 8) Problems/Problem 1"

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{{CEMC box|year=2012|competition=Gauss (Grade 8)|before=First Problem|num-a=2}}

Latest revision as of 21:50, 18 October 2025

Problem

$3 \times (3 + 3) \div 3$ equals

$\text{ (A) }\  6\qquad\text{ (B) }\ 3\qquad\text{ (C) }\ 2\qquad\text{ (D) }\ 12\qquad\text{ (E) }\ 9$

Solution

$3 \times (3 + 3) \div 3 = 3 \times 6 \div 3 = 18 \div 3 = \boxed {\textbf {(A)} 6}$

~anabel.disher

2012 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
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CEMC Gauss (Grade 8)