Difference between revisions of "2012 CEMC Gauss (Grade 8) Problems/Problem 8"
(Created page with "==Problem== The number <math>0.2012</math> is between <math> \text{ (A) }\ 0 \text{ and } \frac{1}{10} \qquad\text{ (B) }\ \frac{1}{10} \text{ and } \frac{1}{5} \qquad\te...") |
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<math>\frac{1}{4} = 0.2500</math> | <math>\frac{1}{4} = 0.2500</math> | ||
| − | <math>\frac{1}{3} = \overline{ | + | <math>\frac{1}{3} = 0.\overline{3333}</math> |
<math>\frac{1}{2} = 0.5000</math> | <math>\frac{1}{2} = 0.5000</math> | ||
| − | From these numbers, we can see that <math>0.2012</math> is between <math>\boxed{\textbf{(C) } \frac{1}{5} \text{and} \frac{1}{4}}</math> | + | From these numbers, we can see that <math>0.2012</math> is between <math>\boxed{\textbf{(C) } \frac{1}{5} \text{ and } \frac{1}{4}}</math> |
| + | {{CEMC box|year=2012|competition=Gauss (Grade 8)|num-b=7|num-a=9}} | ||
Latest revision as of 20:56, 18 October 2025
Problem
The number 
is between
Solution
Converting the fractions into decimals, we have:
From these numbers, we can see that is between 
| 2012 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| CEMC Gauss (Grade 8) | ||
