Difference between revisions of "2012 CEMC Gauss (Grade 8) Problems/Problem 14"

Latest revision as of 20:59, 18 October 2025

Half of the square root of a number is $1$ . The number is

$\text{ (A) }\ 2 \qquad\text{ (B) }\ 4 \qquad\text{ (C) }\ 8 \qquad\text{ (D) }\ 9 \qquad\text{ (E) }\ 16$

Let $x$ be the number that we are looking for. We then have:

$\frac{\sqrt{x}}{2} = 1$

Multiplying both sides by $2$ to get rid of the fraction, we have:

$\sqrt{x} = 2$

We can then square both sides to get rid of the square root, giving:

$x = \boxed {\textbf {(B) } 4}$

~anabel.disher

2012 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources)
Preceded by Problem 13	Followed by Problem 15
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CEMC Gauss (Grade 8)

Revision as of 12:35, 18 June 2025 (view source) Anabel.disher (talk \| contribs) (Created page with "==Problem== Half of the square root of a number is <math>1</math>. The number is <math> \text{ (A) }\ 2 \qquad\text{ (B) }\ 4 \qquad\text{ (C) }\ 8 \qquad\text{ (D) }\ 9...")		Latest revision as of 20:59, 18 October 2025 (view source) Anabel.disher (talk \| contribs)
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		+	{{CEMC box\|year=2012\|competition=Gauss (Grade 8)\|num-b=13\|num-a=15}}