Difference between revisions of "2011 CEMC Gauss (Grade 8) Problems/Problem 3"

Latest revision as of 21:35, 18 October 2025

In the diagram, the value of $y$ is

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$\text{ (A) }\ 60 \qquad\text{ (B) }\ 100\qquad\text{ (C) }\ 120\qquad\text{ (D) }\ 180\qquad\text{ (E) }\ 270$

One entire revolution is $360^{\circ}$ . As suggested by the diagram, the given part of the angle is a right angle. This means that we have:

$y^{\circ} + 90^{\circ} = 360^{\circ}$

Solving for y gives:

$y = \boxed {\textbf {(E) } 270}$

~anabel.disher

2011 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
CEMC Gauss (Grade 8)

@@ Line 1: / Line 1: @@
 ==Problem==
 In the diagram, the value of <math>y</math> is
+{{Template:Image needed}}
 <math> \text{ (A) }\ 60 \qquad\text{ (B) }\ 100\qquad\text{ (C) }\ 120\qquad\text{ (D) }\ 180\qquad\text{ (E) }\ 270 </math>
 ==Solution==
-One entire revolution is <math>360^{\circ}</math>. As suggested by the diagram, the given part of the angle is <math>90^{\circ}</math>. This means that we have:
+One entire revolution is <math>360^{\circ}</math>. As suggested by the diagram, the given part of the angle is a [[right angle]]. This means that we have:
 <math>y^{\circ} + 90^{\circ} = 360^{\circ}</math>
@@ Line 13: / Line 13: @@
 ~anabel.disher
+{{CEMC box|year=2011|competition=Gauss (Grade 8)|num-b=2|num-a=4}}