Difference between revisions of "2011 CEMC Gauss (Grade 8) Problems/Problem 5"

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Latest revision as of 15:01, 19 October 2025

Problem

A bag contains $15$ balls. Exactly $3$ of these balls are red. Alex reaches into the bag and randomly selects one of the balls. What is the probability that the ball Alex selects is red?

$\text{ (A) }\ \frac{1}{5} \qquad\text{ (B) }\ \frac{4}{5} \qquad\text{ (C) }\ \frac{1}{15} \qquad\text{ (D) }\ \frac{1}{4} \qquad\text{ (E) }\ \frac{14}{15}$

Solution

To find the probability that the ball is red, we can divide the number of balls that are red in the bag, and divide it by the total number of balls. This gives:

$\frac{3}{15} = \frac{3 \div 3}{15 \div 3} = \boxed {\textbf {(A) } \frac{1}{5}}$

~anabel.disher

2011 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
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CEMC Gauss (Grade 8)