During AMC testing, the AoPS Wiki is in read-only mode and no edits can be made.

Difference between revisions of "2000 CEMC Gauss (Grade 8) Problems/Problem 9"

(Created page with "==Problem== Of the following five statements, how many are correct? <math>\text{(i) } 20\% \text{ of } 40 = 8 \qquad \text{(ii) } 2^{3} = 8 \qquad \text{(iii) } 7 - 3 \time...")
 
 
Line 24: Line 24:
 
We can also use the fact that <math>a^{2} - b^{2} = (a - b)(a + b)</math>, or [[difference of squares]], to verify <math>3^{2} - 1^{2}</math>:
 
We can also use the fact that <math>a^{2} - b^{2} = (a - b)(a + b)</math>, or [[difference of squares]], to verify <math>3^{2} - 1^{2}</math>:
  
<math>3^{2} - 1^{2} = (3 - 1)(3 + 1) = 4 \times 2 = 8</math>
+
<math>3^{2} - 1^{2} = (3 + 1)(3 - 1) = 4 \times 2 = 8</math>
  
 
The answer is <math>\boxed {\textbf {(D) } 4}</math>.
 
The answer is <math>\boxed {\textbf {(D) } 4}</math>.
  
 
~anabel.disher
 
~anabel.disher
 +
{{CEMC box|year=2000|competition=Gauss (Grade 8)|num-b=8|num-a=10}}

Latest revision as of 12:51, 20 October 2025

Problem

Of the following five statements, how many are correct?

$\text{(i) } 20\% \text{ of } 40 = 8 \qquad \text{(ii) } 2^{3} = 8 \qquad \text{(iii) } 7 - 3 \times 2 = 8 \qquad \text{(iv) } 3^2 - 1^2 = 8 \qquad \text{(v) } 2(6 - 4)^2 = 8$

$\text{ (A) }\ 1 \qquad\text{ (B) }\ 2 \qquad\text{ (C) }\ 3 \qquad\text{ (D) }\ 4 \qquad\text{ (E) }\ 5$

Solution 1

We can just simply verify whether or not each statement is true, and count how many are true:

$20\% \times 40 = \frac{1}{5} \times 40 = 8$, so the first statement is true

$2^{3} = 8$, so the second statement is true

$7 - 3 \times 2 = 7 - 6 = 1$, so the third statement is false

$3^{2} - 1^2 = 9 - 1 = 8$, so the fourth statement is true

$2(6 - 4)^2 = 2(2)^2 = 2 \times 4 = 8$, so the last statement is true

Four of these are correct. Thus, the answer is $\boxed {\textbf {(D) } 4}$.

~anabel.disher

Solution 1.5

We can also use the fact that $a^{2} - b^{2} = (a - b)(a + b)$, or difference of squares, to verify $3^{2} - 1^{2}$:

$3^{2} - 1^{2} = (3 + 1)(3 - 1) = 4 \times 2 = 8$

The answer is $\boxed {\textbf {(D) } 4}$.

~anabel.disher

2000 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 8)