Difference between revisions of "2002 AMC 10B Problems/Problem 2"

Revision as of 22:27, 22 October 2025

For the nonzero numbers a, b, and c, define

$D(a,b,c)=\frac{abc}{a+b+c}$

Find $D(2,4,6)$ .

$\mathrm{(A) \ } 1\qquad \mathrm{(B) \ } 2\qquad \mathrm{(C) \ } 4\qquad \mathrm{(D) \ } 6\qquad \mathrm{(E) \ } 24$

$\frac{2\cdot 4\cdot 6}{2+4+6}=\frac{48}{12}=4\Longrightarrow\mathrm{ (B) \ }$

~Thesmartgreekmathdude

2002 AMC 10B (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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All AMC 10 Problems and Solutions

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 == Solution ==
-<math>\frac{2\cdot 4\cdot 6}{2+4+6}=\frac{48}{12}=4\Longrightarrow\mathrm{ (C) \ }</math>
+<math>\frac{2\cdot 4\cdot 6}{2+4+6}=\frac{48}{12}=4\Longrightarrow\mathrm{ (B) \ }</math>
 ==Video Solution by Daily Dose of Math==