Difference between revisions of "2010 IMO Problems/Problem 3"
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Revision as of 22:36, 23 October 2010
Problem
Find all functions
such that
is a perfect square for all
Author: Gabriel Carroll, USA
Solution
Suppose such function
exist then:
Lemma 1)
Assume for contradiction that
has to be a perfect square
but
.
A square cannot be between 2 consecutive squares. Contradiction. Thus,![]()
Lemma 2)
(we have show that it can't be 0)
Assume for contradiction, that
. Then there must exist a prime number
such that
and
are in the same residue class modulo
.
If
where
is not divisible by
.
If
.
Consider an
such that
, where
is not divisible by
If
.
Consider an
such that
, where
is not divisible by
At least one of
,
is not divisible by
. Hence,
At least one of
,
is divisible by an odd amount of
.
Hence, that number is not a perfect square.
Thus,
,