Difference between revisions of "2005 AMC 12A Problems/Problem 1"
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Latest revision as of 20:12, 3 July 2013
Problem
Two is 
of 
and 
of 
. What is 
?
Solution
.
See also
| 2005 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First question |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
