Difference between revisions of "2014 AMC 12A Problems/Problem 24"
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\textbf{(D) }302\qquad | \textbf{(D) }302\qquad | ||
\textbf{(E) }303\qquad</math> | \textbf{(E) }303\qquad</math> | ||
| + | ==Solution== | ||
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| + | ==See Also== | ||
| + | {{AMC12 box|year=2014|ab=A|num-b=23|num-a=25}} | ||
| + | {{MAA Notice}} | ||
Revision as of 13:37, 8 February 2014
Problem
Let
, and for
, let
. For how many values of
is
?
Solution
See Also
| 2014 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 23 |
Followed by Problem 25 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.