Difference between revisions of "1980 AHSME Problems/Problem 11"
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| + | ==Problem== | ||
| − | If the sum of the first 10 terms and the sum of the first 100 terms of a given arithmetic progression are 100 and 10, respectively, then the sum of first 110 terms is: | + | If the sum of the first <math>10</math> terms and the sum of the first <math>100</math> terms of a given arithmetic progression are <math>100</math> and <math>10</math>, |
| + | respectively, then the sum of first <math>110</math> terms is: | ||
<math>\text{(A)} \ 90 \qquad \text{(B)} \ -90 \qquad \text{(C)} \ 110 \qquad \text{(D)} \ -110 \qquad \text{(E)} \ -100</math> | <math>\text{(A)} \ 90 \qquad \text{(B)} \ -90 \qquad \text{(C)} \ 110 \qquad \text{(D)} \ -110 \qquad \text{(E)} \ -100</math> | ||
| + | |||
| + | == Solution == | ||
| + | <math>\fbox{}</math> | ||
| + | |||
| + | == See also == | ||
| + | {{AHSME box|year=1980|num-b=10|num-a=12}} | ||
| + | |||
| + | [[Category: Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Revision as of 22:44, 2 October 2014
Problem
If the sum of the first 
terms and the sum of the first 
terms of a given arithmetic progression are and ,
respectively, then the sum of first 
terms is:
Solution
See also
| 1980 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
