Difference between revisions of "2004 AMC 10A Problems/Problem 1"
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==Solution== | ==Solution== | ||
| − | There are 6 people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars. <math>\Rightarrow\boxed{\mathrm{(A)}\ 250}</math> | + | There are <math>6</math> people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars. <math>\Rightarrow\boxed{\mathrm{(A)}\ 250}</math> |
== See also == | == See also == | ||
Revision as of 08:03, 29 November 2014
Problem
You and five friends need to raise 
dollars in donations for a charity, dividing the fundraising equally. How many dollars will each of you need to raise?
Solution
There are 
people to split the dollars among, so each person must raise 
dollars. 
See also
| 2004 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
