Difference between revisions of "2017 AMC 8 Problems/Problem 4"
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==Solution== | ==Solution== | ||
We can approximate <math>7,928,564</math> to <math>8,000,000</math> and <math>0.000315</math> to <math>0.0003.</math> Multiplying the two yields <math>2400.</math> Thus, it shows our answer is <math>\boxed{\textbf{(D)}\ 2400}.</math> | We can approximate <math>7,928,564</math> to <math>8,000,000</math> and <math>0.000315</math> to <math>0.0003.</math> Multiplying the two yields <math>2400.</math> Thus, it shows our answer is <math>\boxed{\textbf{(D)}\ 2400}.</math> | ||
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| + | ==Video Solution (CREATIVE THINKING!!!)== | ||
| + | https://youtu.be/5wa99PngBSo | ||
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| + | ~Education, the Study of Everything | ||
==Video Solution== | ==Video Solution== | ||
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{{MAA Notice}} | {{MAA Notice}} | ||
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| + | [[Category:Introductory Algebra Problems]] | ||
Latest revision as of 19:04, 7 June 2025
Problem
When 
is multiplied by 
the product is closest to which of the following?
Solution
We can approximate to 
and to 
Multiplying the two yields 
Thus, it shows our answer is 
Video Solution (CREATIVE THINKING!!!)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
| 2017 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
