Difference between revisions of "2022 SSMO Speed Round Problems/Problem 6"

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==Problem==
  
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At the beginning of day <math>1</math>, there is a single bacterium in a petri dish. During each day, each bacterium in the petri dish divides into <math>a>1</math> new bacteria, and <math>b\ge 1</math> bacteria are added to the petri dish (these bacteria do not divide on the day they were added). For example, at the end of day <math>1</math>, there are <math>a+b</math> bacteria in the petri dish. If, at the end of day <math>4</math>, the number of bacteria in the petri dish is a multiple of <math>48</math>, find the minimum possible value of <math>a+b</math>.
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==Solution==

Latest revision as of 19:14, 2 May 2025

Problem

At the beginning of day $1$, there is a single bacterium in a petri dish. During each day, each bacterium in the petri dish divides into $a>1$ new bacteria, and $b\ge 1$ bacteria are added to the petri dish (these bacteria do not divide on the day they were added). For example, at the end of day $1$, there are $a+b$ bacteria in the petri dish. If, at the end of day $4$, the number of bacteria in the petri dish is a multiple of $48$, find the minimum possible value of $a+b$.

Solution