Difference between revisions of "2023 AMC 10A Problems/Problem 3"

Latest revision as of 22:08, 9 November 2023

Redirect to:

@@ Line 1: / Line 1: @@
+#redirect[[2023 AMC 12A Problems/Problem 3]]
-==Problem==
-How many positive perfect squares less than <math>2023</math> are divisible by <math>5</math>?
-<cmath>\textbf{(A) } 8 \qquad\textbf{(B) }9 \qquad\textbf{(C) }10 \qquad\textbf{(D) }11 \qquad\textbf{(E) } 12</cmath>
-==Solution 1==
-Note that <math>45^{2}=2025</math> so the list is <math>5,10,15,20,25,30,35,40</math> there are <math>8</math> elements so the answer is <math>\boxed{textbf{(A) 8}}</math>.
-~zhenghua
-==See Also==
-{{AMC12 box|year=2023|ab=A|num-b=2|num-a=4}}
-{{AMC10 box|year=2023|ab=A|num-b=2|num-a=4}}
-{{MAA Notice}}