Difference between revisions of "2023 USAJMO Problems/Problem 1"
Markma2010 (talk | contribs) (→Solution 1) |
m (→Solution 1) |
||
| Line 39: | Line 39: | ||
Proceed as above. ~eevee9406 | Proceed as above. ~eevee9406 | ||
| + | |||
| + | note: idk gang i think the first factorization is more readily apparent but the second factorization is very orz indeed | ||
| + | ~Aarush12 | ||
==See Also== | ==See Also== | ||
{{USAJMO newbox|year=2023|before=First Question|num-a=2}} | {{USAJMO newbox|year=2023|before=First Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 23:18, 17 March 2025
Problem
Find all triples of positive integers
that satisfy the equation
Solution 1
We claim that the only solutions are
and its permutations.
Factoring the above squares and canceling the terms gives you:
Jumping on the coefficients in front of the
,
,
terms, we factor into:
Realizing that the only factors of 2023 that could be expressed as
are
,
, and
, we simply find that the only solutions are
by inspection.
-Max
Alternatively, a more obvious factorization is:
Proceed as above. ~eevee9406
note: idk gang i think the first factorization is more readily apparent but the second factorization is very orz indeed ~Aarush12
See Also
| 2023 USAJMO (Problems • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 | ||
| All USAJMO Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.