Difference between revisions of "2019 AMC 8 Problems/Problem 15"
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On a beach <math>50</math> people are wearing sunglasses and <math>35</math> people are wearing caps. Some people are wearing both sunglasses and caps. If one of the people wearing a cap is selected at random, the probability that this person is also wearing sunglasses is <math>\frac{2}{5}</math>. If instead, someone wearing sunglasses is selected at random, what is the probability that this person is also wearing a cap? | On a beach <math>50</math> people are wearing sunglasses and <math>35</math> people are wearing caps. Some people are wearing both sunglasses and caps. If one of the people wearing a cap is selected at random, the probability that this person is also wearing sunglasses is <math>\frac{2}{5}</math>. If instead, someone wearing sunglasses is selected at random, what is the probability that this person is also wearing a cap? | ||
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Latest revision as of 20:57, 5 June 2025
Problem
On a beach people are wearing sunglasses and
people are wearing caps. Some people are wearing both sunglasses and caps. If one of the people wearing a cap is selected at random, the probability that this person is also wearing sunglasses is
. If instead, someone wearing sunglasses is selected at random, what is the probability that this person is also wearing a cap?
Solution 1
The number of people wearing caps and sunglasses is
. So then, 14 people out of the 50 people wearing sunglasses also have caps.
Solution 2
Let be the event that a randomly selected person is wearing sunglasses, and let
be the event that a randomly selected person is wearing a cap. We can write
in two ways:
or
. Suppose there are
people in total. Then
and
Additionally, we know that the probability that someone is wearing sunglasses given that they wear a cap is
, so
. We let
, which is the quantity we want to find, be equal to
. Substituting in, we get
Note: This solution makes use of the dependent events probability formula, , where
represents the probability that
occurs given that
has already occurred and
represents the probability of both
and
happening.
~ cxsmi
Video Solution by EzLx
~EzLx CookeMonster SirCookies
Video Solution
https://youtu.be/6xNkyDgIhEE?t=250pih-jsm
See Also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.