Difference between revisions of "1999 CEMC Gauss (Grade 7) Problems/Problem 13"
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==Problem== | ==Problem== | ||
In the diagram, the percent of small squares that are shaded is | In the diagram, the percent of small squares that are shaded is | ||
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<math>\text{(A)}\ 9 \qquad \text{(B)}\ 33 \qquad \text{(C)}\ 36 \qquad \text{(D)}\ 56.25 \qquad \text{(E)}\ 64</math> | <math>\text{(A)}\ 9 \qquad \text{(B)}\ 33 \qquad \text{(C)}\ 36 \qquad \text{(D)}\ 56.25 \qquad \text{(E)}\ 64</math> | ||
==Solution== | ==Solution== | ||
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Since the large square has a side length of <math>5</math>, its area is <math>5^2 = 25</math>. | Since the large square has a side length of <math>5</math>, its area is <math>5^2 = 25</math>. | ||
| − | Therefore, the percentage of small squares that are shaded is <math>\frac{9}{25} = \frac{9 * 4}{25 * 4} = \frac{36}{100} = 36%</math>. So, the answer is <math>\boxed {\textbf {(C)} 36}</math>. | + | Therefore, the percentage of small squares that are shaded is <math>\frac{9}{25} = \frac{9 * 4}{25 * 4} = \frac{36}{100} = 36\%</math>. So, the answer is <math>\boxed {\textbf {(C)} 36}</math>. |
Latest revision as of 12:27, 22 April 2025
Problem
In the diagram, the percent of small squares that are shaded is
An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.
Solution
Using the diagram, we can see that nine of the rectangles are shaded, and that the large square has a side length of 
.
Since the large square has a side length of , its area is 
.
Therefore, the percentage of small squares that are shaded is 
. So, the answer is 
.
