Difference between revisions of "2012 CEMC Gauss (Grade 8) Problems/Problem 5"
(Undo revision 247023 by Anabel.disher (talk)) (Tag: Undo) |
|||
Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
− | + | How many more coins does it take to make one dollar (100) using only nickels(5 coins) than it takes to make one dollar using only dimes(10 coins)?<!--Note: this is how the question was written--> | |
− | <math> \text{ (A) }\ | + | <math> \text{ (A) }\ 15\qquad\text{ (B) }\ 10\qquad\text{ (C) }\ 75\qquad\text{ (D) }\ 64\qquad\text{ (E) }\ 54 </math> |
==Solution== | ==Solution== | ||
− | <math> | + | Since a dollar is <math>100</math> cents and a nickel is <math>5</math> cents, there are <math>\frac{100}{5} = 20</math> nickels in a dollar. |
− | <math>\frac{ | + | Using this logic for dimes and the fact that a dime is <math>10</math> cents, there are <math>\frac{100}{10} = 10</math> dimes in a dollar. |
− | + | Thus, it takes <math>20 - 10 = \boxed{\textbf{(B) } 10}</math> more coins to make a dollar using only nickels than it takes to make one dollar using only dimes. | |
~anabel.disher | ~anabel.disher |
Latest revision as of 16:33, 20 April 2025
Problem
How many more coins does it take to make one dollar (100) using only nickels(5 coins) than it takes to make one dollar using only dimes(10 coins)?
Solution
Since a dollar is cents and a nickel is
cents, there are
nickels in a dollar.
Using this logic for dimes and the fact that a dime is cents, there are
dimes in a dollar.
Thus, it takes more coins to make a dollar using only nickels than it takes to make one dollar using only dimes.
~anabel.disher