Difference between revisions of "2011 CEMC Gauss (Grade 8) Problems/Problem 1"

(Created page with "==Problem== If <math>\frac{8}{12} = \frac{\framebox {}}{3}</math>, then the value represented by <math>\framebox {}</math> is <math> \text{ (A) }\ 24\qquad\text{ (B) }\ 1\q...")
 
 
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<math>\frac{8}{12} = \frac{8 \div 4}{12 \div 4} = \frac{2}{3}</math>
 
<math>\frac{8}{12} = \frac{8 \div 4}{12 \div 4} = \frac{2}{3}</math>
  
Since the numerator is <math>2</math>, the answer is <math>\boxed {\textbf {(D) }2}</math>.
+
Since the numerator is <math>2</math> and we have the same denominator, the answer is <math>\boxed {\textbf {(D) }2}</math>.
  
 
~anabel.disher
 
~anabel.disher
 +
{{CEMC box|year=2011|competition=Gauss (Grade 8)|before=First Problem|num-a=2}}

Latest revision as of 22:34, 18 October 2025

Problem

If $\frac{8}{12} = \frac{\framebox {}}{3}$, then the value represented by $\framebox {}$ is

$\text{ (A) }\  24\qquad\text{ (B) }\ 1\qquad\text{ (C) }\ 12\qquad\text{ (D) }\ 2\qquad\text{ (E) }\ 4$

Solution

$\frac{12}{3} = 4$, meaning we can divide the numerator and denominator by $4$ to arrive at our answer.

$\frac{8}{12} = \frac{8 \div 4}{12 \div 4} = \frac{2}{3}$

Since the numerator is $2$ and we have the same denominator, the answer is $\boxed {\textbf {(D) }2}$.

~anabel.disher

2011 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 8)