Difference between revisions of "2024 SSMO Relay Round 2 Problems/Problem 1"
(Created page with "==Problem== In a regular hexagon <math>ABCDEF</math>, let <math>X</math> be a point inside the hexagon such that <math>XA=XB=3.</math> If the area of the hexagon is <math>6\s...") |
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+ | Let <math>s</math> be the sidelength of the hexagon. We have <math>\frac{6s^2\sqrt{3}}{4} = 6\sqrt{3}\implies s = 2.</math> Let <math>h</math> be the distance from <math>X</math> to <math>AB.</math> Thus, we have <math>\sqrt{h^2+\left(\frac{s}{2}\right)^2} = 3\implies h^2 = 8\implies h = 2\sqrt{2}.</math> Since the distance from <math>AB</math> to <math>DE</math> is <math>2\sqrt{3},</math> <cmath>XE = \sqrt{(2\sqrt{3}-2\sqrt{2})^2+\left(\frac{s}{2}\right)^2}\implies XE^2 = 21-8\sqrt{6}\implies 21-8+6 = \boxed{19}.</cmath> | ||
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+ | ~SMO_Team |
Latest revision as of 14:43, 10 September 2025
Problem
In a regular hexagon , let
be a point inside the hexagon such that
If the area of the hexagon is
, then
for squarefree
. Find
.
Solution
Let be the sidelength of the hexagon. We have
Let
be the distance from
to
Thus, we have
Since the distance from
to
is
~SMO_Team