Difference between revisions of "2001 CEMC Pascal Problems/Problem 10"
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| − | Dean scored a total of <math>252</math> points in <math> | + | Dean scored a total of <math>252</math> points in <math>28</math> basketball games. Ruth played <math>10</math> fewer games than Dean. Her scoring average was <math>0.5</math> points per game higher than Dean's scoring average. How many points, in total, did Ruth score? |
<math> \text{ (A) }\ 153 \qquad\text{ (B) }\ 171 \qquad\text{ (C) }\ 180 \qquad\text{ (D) }\ 266 \qquad\text{ (E) }\ 144</math> | <math> \text{ (A) }\ 153 \qquad\text{ (B) }\ 171 \qquad\text{ (C) }\ 180 \qquad\text{ (D) }\ 266 \qquad\text{ (E) }\ 144</math> | ||
Latest revision as of 17:26, 5 July 2025
Problem
Dean scored a total of 
points in 
basketball games. Ruth played 
fewer games than Dean. Her scoring average was 
points per game higher than Dean's scoring average. How many points, in total, did Ruth score?
Solution
We can first find Dean's average and use it to find the average of Ruth's points, the number of games that Ruth played, then use that to find out how many points Ruth had in total.
Dean's average was 
points per game. Since Ruth's average was points higher, her average was 
.
Since Dean played games, Ruth played 
games.
The number of points that Ruth got was then 
~anabel.disher
