Difference between revisions of "2005 CEMC Pascal Problems/Problem 4"
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Dividing this by the number of balls, we have; | Dividing this by the number of balls, we have; | ||
− | <math>\frac{4}{6} = \frac{4 \div 2}{6 \div 2} = \boxed {\textbf {(D) } frac{2}{3}}</math> | + | <math>\frac{4}{6} = \frac{4 \div 2}{6 \div 2} = \boxed {\textbf {(D) } \frac{2}{3}}</math> |
~anabel.disher | ~anabel.disher |
Latest revision as of 17:42, 5 July 2025
Problem
Six balls, numbered are placed in a hat. Each ball is equally likely to be chosen. If one ball is chosen, what is the probability that the number on the selected ball is a prime number?
Solution
To find the probability of the ball having a prime number, we can find the number of ways that we can select a ball with a prime number divided by the number of balls.
From the list, the prime numbers are and
. This gives us
ways to select a ball with a prime number on it.
Dividing this by the number of balls, we have;
~anabel.disher