Difference between revisions of "Descartes' Circle Formula"

Latest revision as of 16:22, 22 August 2025

Descartes' Circle Formula is a relation held between four mutually tangent circles.

Definition of Curvature

When discussing mutually tangent circles (or arcs), it is convenient to refer to the curvature of a circle rather than its radius. We define curvature as follows. Suppose that circle A of radius $r_a$ is externally tangent to circle B of radius $r_b$ . Then the curvatures of the circles are simply the reciprocals of their radii, $\frac{1}{r_a}$ and $\frac{1}{r_b}$ .

If circle $A$ is internally tangent to circle $B$ , however, a the curvature of circle $A$ is still $\frac{1}{r_a}$ , while the curvature of circle B is $-\frac{1}{r_b}$ , the opposite of the reciprocal of its radius.

$[asy] size(200); defaultpen(linewidth(0.7)); draw(Circle(origin,0.5)); draw(Circle((1.5,0),1)); dot(origin^^(1.5,0)^^(0.5,0)); draw(origin--(1.5,0)); label("$1/2$", (0.25,0), N); label("$1$", (1,0), N); label("$A$", origin, SW); label("$B$", (1.5,0), SE); [/asy]$

In the above diagram, the curvature of circle $A$ is $2$ while the curvature of circle $B$ is $1$ .

$[asy] size(150); defaultpen(linewidth(0.7)); draw(Circle((1.25,0),0.25)); draw(Circle((1.5,0),0.5)); dot((1,0)^^(1.5,0)^^(1.25,0)^^(2,0)); draw((1,0)--(2,0)); label("$1/2$", (1.125,0), N); label("$1$", (1.75,0), N); label("$A$", (1.25,0), SW); label("$B$", (1.5,0), SE); [/asy]$

In the above diagram, the curvature of circle $A$ is still $2$ while the curvature of circle $B$ is $-1$ .

Statement

When four circles are pairwise tangent, with respective curvatures $r_1, r_2, r_3,$ and $r_4$ , then the following equation holds:

$(r_1 + r_2 + r_3 + r_4)^2 = 2(r_1^2 + r_2^2 + r_3^2 + r_4^2)$ .

Proof

Waiting for the MAA to grant permission to avoid copyright issues...

Problems

@@ Line 38: / Line 38: @@
 ==Statement==
-When four circles <math>A, B, C,</math> and <math>D</math> are pairwise tangent, with respective curvatures <math>a, b, c,</math> and <math>d</math>, then the following equation holds:
+When four circles are pairwise tangent, with respective curvatures <math>r_1, r_2, r_3,</math> and <math>r_4</math>, then the following equation holds:
-<math>(a+b+c+d)^2 = 2(a^2+b^2+c^2+d^2)</math>.
+<math>(r_1 + r_2 + r_3 + r_4)^2 = 2(r_1^2 + r_2^2 + r_3^2 + r_4^2)</math>.
 ==Proof==
+Waiting for the MAA to grant permission to avoid copyright issues...
 ==Problems==

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