Difference between revisions of "2005 iTest Problems/Problem 3"
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==Solution 1== | ==Solution 1== | ||
We have to arrange 5 elements in a row. These are Carrie, Miranda, Charlotte, Samantha, and the empty seat. Since there are five things to arrange, our answer is <math>5!=\boxed{120}</math> | We have to arrange 5 elements in a row. These are Carrie, Miranda, Charlotte, Samantha, and the empty seat. Since there are five things to arrange, our answer is <math>5!=\boxed{120}</math> | ||
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| + | ==See Also== | ||
| + | {{iTest box|year=2005|num-b=2|num-a=4}} | ||
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| + | [[Category: Introductory Combinatorics Problems]] | ||
Latest revision as of 19:06, 13 October 2025
Problem
Carrie, Miranda, Charlotte, and Samantha are sitting at a table with 
numbered chairs (numbered 
through ). One chair is left open for Big, should he decide to join the four for lunch. In how many distinct ways can the four women occupy the table?
Solution 1
We have to arrange 5 elements in a row. These are Carrie, Miranda, Charlotte, Samantha, and the empty seat. Since there are five things to arrange, our answer is 
See Also
| 2005 iTest (Problems, Answer Key) | ||
| Preceded by: Problem 2 |
Followed by: Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 • 51 • 52 • 53 • 54 • 55 • 56 • 57 • 58 • 59 • 60 • TB1 • TB2 • TB3 • TB4 | ||
