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Difference between revisions of "2009 AMC 12A Problems/Problem 1"

m (New page: == Problem == Kim's flight took off from Newark at 10:34 AM and landed in Miami at 1:18 PM. Both cities are in the same time zone. If her flight took <math>h</math> hours and <math>m</math...)
 
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== Solution ==
 
== Solution ==
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There is <math>1</math> hour and <math>60-34 = 26</math> minutes between 10:34 AM and noon; and there is <math>1</math> hour and <math>18</math> minutes between noon and 1:18 PM. Hence the flight took <math>2</math> hours and <math>26 + 18 = 44</math> minutes, and <math>h+m= 46\ \textbf{(A)}</math>.
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There is <math>1</math> hour and <math>60-34 = 26</math> minutes between 10:34 AM and noon; and there is <math>1</math> hour and <math>18</math> minutes between noon and 1:18 PM. Hence the flight took <math>2</math> hours and <math>26 + 18 = 44</math> minutes,and 2+44=46s0 <math>h+m= 46\ \textbf{(A)}</math>.
  
 
== See Also ==
 
== See Also ==
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[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 15:24, 1 July 2025

Problem

Kim's flight took off from Newark at 10:34 AM and landed in Miami at 1:18 PM. Both cities are in the same time zone. If her flight took $h$ hours and $m$ minutes, with $0 < m < 60$, what is $h + m$?

$\textbf{(A)}\ 46 \qquad \textbf{(B)}\ 47 \qquad \textbf{(C)}\ 50 \qquad \textbf{(D)}\ 53 \qquad \textbf{(E)}\ 54$

Solution

There is $1$ hour and $60-34 = 26$ minutes between 10:34 AM and noon; and there is $1$ hour and $18$ minutes between noon and 1:18 PM. Hence the flight took $2$ hours and $26 + 18 = 44$ minutes,and 2+44=46s0 $h+m= 46\ \textbf{(A)}$.

See Also

2009 AMC 12A (Problems • Answer Key • Resources)
Preceded by
First question 		Followed by
Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 12 Problems and Solutions

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