Difference between revisions of "1990 AJHSME Problems/Problem 15"
5849206328x (talk | contribs) (Created page with '==Problem== The area of this figure is <math>100\text{ cm}^2</math>. Its perimeter is <asy> draw((0,2)--(2,2)--(2,1)--(3,1)--(3,0)--(1,0)--(1,1)--(0,1)--cycle,linewidth(1)); …') |
|||
| Line 22: | Line 22: | ||
{{AJHSME box|year=1990|num-b=14|num-a=16}} | {{AJHSME box|year=1990|num-b=14|num-a=16}} | ||
[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 00:06, 5 July 2013
Problem
The area of this figure is 
. Its perimeter is
![[asy] draw((0,2)--(2,2)--(2,1)--(3,1)--(3,0)--(1,0)--(1,1)--(0,1)--cycle,linewidth(1)); draw((1,2)--(1,1)--(2,1)--(2,0),dashed); [/asy]](http://latex.artofproblemsolving.com/4/b/8/4b8e9c1dd2a6fd8adac856d778af57eb39bc2aa3.png)
Solution
Since the area of the whole figure is 
, each square has an area of 
and the side length is 
.
There are 
sides of this length, so the perimeter is 
.
See Also
| 1990 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 14 |
Followed by Problem 16 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
