Difference between revisions of "1961 AHSME Problems/Problem 2"
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Rockmanex3 (talk | contribs) (Solution to Problem 2) |
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− | An automobile travels a/6 | + | == Problem == |
+ | |||
+ | An automobile travels <math>a/6</math> feet in <math>r</math> seconds. If this rate is maintained for <math>3</math> minutes, how many yards does it travel in <math>3</math> minutes? | ||
+ | |||
+ | <math>\textbf{(A)}\ \frac{a}{1080r}\qquad | ||
+ | \textbf{(B)}\ \frac{30r}{a}\qquad | ||
+ | \textbf{(C)}\ \frac{30a}{r}\qquad | ||
+ | \textbf{(D)}\ \frac{10r}{a}\qquad | ||
+ | \textbf{(E)}\ \frac{10a}{r} </math> | ||
+ | |||
+ | ==Solution== | ||
+ | Use dimensional analysis. | ||
+ | <cmath>\frac{a/6 \text{ feet}}{r \text{ seconds}} \cdot \frac{1 \text{ yard}}{3 \text{ feet}} \cdot \frac{60 \text{ seconds}}{1 \text{ minute}} \cdot 3 \text{ minutes}</cmath> | ||
+ | <cmath>\frac{10a}{r} \text{ yards}</cmath> | ||
+ | The answer is <math>\boxed{\textbf{(E)}}</math>. | ||
+ | |||
+ | ==See Also== | ||
+ | {{AHSME 40p box|year=1961|num-b=1|num-a=3}} | ||
+ | |||
+ | {{MAA Notice}} |
Latest revision as of 19:30, 17 May 2018
Problem
An automobile travels feet in
seconds. If this rate is maintained for
minutes, how many yards does it travel in
minutes?
Solution
Use dimensional analysis.
The answer is
.
See Also
1961 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.