Difference between revisions of "1992 AJHSME Problems/Problem 2"
5849206328x (talk | contribs) (Created page with '==Problem== Which of the following is not equal to <math>\dfrac{5}{4}</math>? <math>\text{(A)}\ \dfrac{10}{8} \qquad \text{(B)}\ 1\dfrac{1}{4} \qquad \text{(C)}\ 1\dfrac{3}{12}…') |
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<math>\text{(A)}\ \dfrac{10}{8} \qquad \text{(B)}\ 1\dfrac{1}{4} \qquad \text{(C)}\ 1\dfrac{3}{12} \qquad \text{(D)}\ 1\dfrac{1}{5} \qquad \text{(E)}\ 1\dfrac{10}{40}</math> | <math>\text{(A)}\ \dfrac{10}{8} \qquad \text{(B)}\ 1\dfrac{1}{4} \qquad \text{(C)}\ 1\dfrac{3}{12} \qquad \text{(D)}\ 1\dfrac{1}{5} \qquad \text{(E)}\ 1\dfrac{10}{40}</math> | ||
| − | ==Solution== | + | ==Solution 1== |
The fraction in question is equal to <math>1.25</math>. Expressing all of the choices we have, | The fraction in question is equal to <math>1.25</math>. Expressing all of the choices we have, | ||
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It's clear then that choice <math>\boxed{\text{D}}</math> is the answer. | It's clear then that choice <math>\boxed{\text{D}}</math> is the answer. | ||
| + | |||
| + | ==Solution 2 (low on time)== | ||
| + | A quick glance shows that <math>\boxed{\text{D}}</math> is the only answer with a denominator that does not have 4 as a factor, so it is unlikely that it will simplify into <math>\frac{5}{4}</math>. | ||
==See Also== | ==See Also== | ||
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{{AJHSME box|year=1992|num-b=1|num-a=3}} | {{AJHSME box|year=1992|num-b=1|num-a=3}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 12:36, 27 June 2023
Problem
Which of the following is not equal to 
?
Solution 1
The fraction in question is equal to 
. Expressing all of the choices we have,
.
It's clear then that choice 
is the answer.
Solution 2 (low on time)
A quick glance shows that is the only answer with a denominator that does not have 4 as a factor, so it is unlikely that it will simplify into 
.
See Also
| 1992 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
