Difference between revisions of "2010 AMC 12A Problems/Problem 1"
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== Solution == | == Solution == | ||
| − | <math>20-2010+201+2010-201+20=20+20= | + | <math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>. |
| − | == See | + | ==Video Solution== |
| + | https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_ | ||
| + | |||
| + | == See Also == | ||
{{AMC12 box|year=2010|before=First Problem|num-a=2|ab=A}} | {{AMC12 box|year=2010|before=First Problem|num-a=2|ab=A}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 00:16, 11 October 2025
Contents
Problem
What is 
?
Solution
.
Video Solution
https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_
See Also
| 2010 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
