Difference between revisions of "1986 AJHSME Problems/Problem 4"
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+ | Approximating <math>40.37</math> instead of <math>1.8</math> is more effective because larger numbers are less affected by absolute changes (e.g <math>1001</math> is much closer relatively to <math>1000</math> than <math>2</math> is to <math>1</math>). | ||
<math>74</math> is the closest to <math>72</math>, so the answer is <math>\boxed{\text{C}}</math>. | <math>74</math> is the closest to <math>72</math>, so the answer is <math>\boxed{\text{C}}</math>. | ||
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{{AJHSME box|year=1986|num-b=3|num-a=5}} | {{AJHSME box|year=1986|num-b=3|num-a=5}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 02:17, 24 November 2017
Problem
The product is closest to
Solution
Approximating instead of
is more effective because larger numbers are less affected by absolute changes (e.g
is much closer relatively to
than
is to
).
is the closest to
, so the answer is
.
See Also
1986 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.